Base | Representation |
---|---|
bin | 111100101000100111… |
… | …1011010010000001011 |
3 | 110110002200212121212122 |
4 | 1321101033122100023 |
5 | 4113133233404232 |
6 | 135452451201455 |
7 | 12256526564153 |
oct | 1712117322013 |
9 | 413080777778 |
10 | 130212013067 |
11 | 5024a317744 |
12 | 2129b8a628b |
13 | c381aa6a56 |
14 | 64336d7763 |
15 | 35c1792312 |
hex | 1e513da40b |
130212013067 has 2 divisors, whose sum is σ = 130212013068. Its totient is φ = 130212013066.
The previous prime is 130212013021. The next prime is 130212013069. The reversal of 130212013067 is 760310212031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130212013067 - 28 = 130212012811 is a prime.
Together with 130212013069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (130212013069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106006533 + 65106006534.
It is an arithmetic number, because the mean of its divisors is an integer number (65106006534).
Almost surely, 2130212013067 is an apocalyptic number.
130212013067 is a deficient number, since it is larger than the sum of its proper divisors (1).
130212013067 is an equidigital number, since it uses as much as digits as its factorization.
130212013067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 130212013067 its reverse (760310212031), we get a palindrome (890522225098).
The spelling of 130212013067 in words is "one hundred thirty billion, two hundred twelve million, thirteen thousand, sixty-seven".
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