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130213100333 is a prime number
BaseRepresentation
bin111100101000101001…
…1100011101100101101
3110110002202220212022202
41321101103203230231
54113134023202313
6135452530351245
712256542043061
oct1712123435455
9413082825282
10130213100333
115024a99a608
12212a012b525
13c3820978c4
1464338dbaa1
1535c1909558
hex1e514e3b2d

130213100333 has 2 divisors, whose sum is σ = 130213100334. Its totient is φ = 130213100332.

The previous prime is 130213100309. The next prime is 130213100401. The reversal of 130213100333 is 333001312031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102050219209 + 28162881124 = 319453^2 + 167818^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130213100333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130213100033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106550166 + 65106550167.

It is an arithmetic number, because the mean of its divisors is an integer number (65106550167).

Almost surely, 2130213100333 is an apocalyptic number.

It is an amenable number.

130213100333 is a deficient number, since it is larger than the sum of its proper divisors (1).

130213100333 is an equidigital number, since it uses as much as digits as its factorization.

130213100333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 130213100333 its reverse (333001312031), we get a palindrome (463214412364).

The spelling of 130213100333 in words is "one hundred thirty billion, two hundred thirteen million, one hundred thousand, three hundred thirty-three".