Base | Representation |
---|---|
bin | 111100101000101001… |
… | …1101000100000011111 |
3 | 110110002202221212100022 |
4 | 1321101103220200133 |
5 | 4113134024320111 |
6 | 135452531022355 |
7 | 12256542154361 |
oct | 1712123504037 |
9 | 413082855308 |
10 | 130213120031 |
11 | 5024aa03395 |
12 | 212a013a9bb |
13 | c3820a3867 |
14 | 6433904d31 |
15 | 35c19102db |
hex | 1e514e881f |
130213120031 has 2 divisors, whose sum is σ = 130213120032. Its totient is φ = 130213120030.
The previous prime is 130213120027. The next prime is 130213120057. The reversal of 130213120031 is 130021312031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130213120031 - 22 = 130213120027 is a prime.
It is a super-2 number, since 2×1302131200312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130213119991 and 130213120009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130213120061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106560015 + 65106560016.
It is an arithmetic number, because the mean of its divisors is an integer number (65106560016).
Almost surely, 2130213120031 is an apocalyptic number.
130213120031 is a deficient number, since it is larger than the sum of its proper divisors (1).
130213120031 is an equidigital number, since it uses as much as digits as its factorization.
130213120031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 130213120031 its reverse (130021312031), we get a palindrome (260234432062).
The spelling of 130213120031 in words is "one hundred thirty billion, two hundred thirteen million, one hundred twenty thousand, thirty-one".
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