Base | Representation |
---|---|
bin | 1011110101111100001100… |
… | …1010010011101010111101 |
3 | 1201002211022012002111222111 |
4 | 2331133003022103222331 |
5 | 3201320130423231214 |
6 | 43405524545014021 |
7 | 2512521310631425 |
oct | 275370312235275 |
9 | 51084265074874 |
10 | 13021320133309 |
11 | 4170346828484 |
12 | 1563751924311 |
13 | 735b9c9ca007 |
14 | 33034178d485 |
15 | 178aab26d5c4 |
hex | bd7c3293abd |
13021320133309 has 2 divisors, whose sum is σ = 13021320133310. Its totient is φ = 13021320133308.
The previous prime is 13021320133271. The next prime is 13021320133319. The reversal of 13021320133309 is 90333102312031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12920070802500 + 101249330809 = 3594450^2 + 318197^2 .
It is a cyclic number.
It is not a de Polignac number, because 13021320133309 - 27 = 13021320133181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13021320133319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510660066654 + 6510660066655.
It is an arithmetic number, because the mean of its divisors is an integer number (6510660066655).
Almost surely, 213021320133309 is an apocalyptic number.
It is an amenable number.
13021320133309 is a deficient number, since it is larger than the sum of its proper divisors (1).
13021320133309 is an equidigital number, since it uses as much as digits as its factorization.
13021320133309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 31.
The spelling of 13021320133309 in words is "thirteen trillion, twenty-one billion, three hundred twenty million, one hundred thirty-three thousand, three hundred nine".
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