130213233111301 has 4 divisors (see below), whose sum is σ = 132420237062400. Its totient is φ = 128006229160204.

The previous prime is 130213233111289. The next prime is 130213233111307. The reversal of 130213233111301 is 103111332312031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130213233111301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130213233111307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1103501975461 + ... + 1103501975578.

It is an arithmetic number, because the mean of its divisors is an integer number (33105059265600).

Almost surely, 2^{130213233111301} is an apocalyptic number.

It is an amenable number.

130213233111301 is a deficient number, since it is larger than the sum of its proper divisors (2207003951099).

130213233111301 is an equidigital number, since it uses as much as digits as its factorization.

130213233111301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2207003951098.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 130213233111301 its reverse (103111332312031), we get a palindrome (233324565423332).

The spelling of 130213233111301 in words is "one hundred thirty trillion, two hundred thirteen billion, two hundred thirty-three million, one hundred eleven thousand, three hundred one".