Base | Representation |
---|---|
bin | 1011110101111100100010… |
… | …1001001001011101010111 |
3 | 1201002211112121011010002020 |
4 | 2331133020221021131113 |
5 | 3201320322444312043 |
6 | 43405542032144223 |
7 | 2512523505442551 |
oct | 275371051113527 |
9 | 51084477133066 |
10 | 13021412104023 |
11 | 4170393735434 |
12 | 1563778698073 |
13 | 735bb5a8bc5b |
14 | 33034da904d1 |
15 | 178ab4388e83 |
hex | bd7c8a49757 |
13021412104023 has 64 divisors (see below), whose sum is σ = 17840940429312. Its totient is φ = 8445838728960.
The previous prime is 13021412103991. The next prime is 13021412104031. The reversal of 13021412104023 is 32040121412031.
It is not a de Polignac number, because 13021412104023 - 25 = 13021412103991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13021412103984 and 13021412104002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13021412104223) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3252911340 + ... + 3252915342.
It is an arithmetic number, because the mean of its divisors is an integer number (278764694208).
Almost surely, 213021412104023 is an apocalyptic number.
13021412104023 is a deficient number, since it is larger than the sum of its proper divisors (4819528325289).
13021412104023 is a wasteful number, since it uses less digits than its factorization.
13021412104023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4964.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13021412104023 its reverse (32040121412031), we get a palindrome (45061533516054).
The spelling of 13021412104023 in words is "thirteen trillion, twenty-one billion, four hundred twelve million, one hundred four thousand, twenty-three".
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