Base | Representation |
---|---|
bin | 11101100110111100110110… |
… | …000111001011111011001011 |
3 | 122002001220122011220102220122 |
4 | 131212330312013023323023 |
5 | 114032011100423112224 |
6 | 1140542130230013455 |
7 | 36300041344000313 |
oct | 3546746607137313 |
9 | 562056564812818 |
10 | 130220021300939 |
11 | 38546001217129 |
12 | 127316197a728b |
13 | 57879067c959b |
14 | 242297b30c443 |
15 | 100c4c559515e |
hex | 766f361cbecb |
130220021300939 has 2 divisors, whose sum is σ = 130220021300940. Its totient is φ = 130220021300938.
The previous prime is 130220021300909. The next prime is 130220021301011. The reversal of 130220021300939 is 939003120022031.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (939003120022031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130220021300939 - 232 = 130215726333643 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130220021300899 and 130220021300908.
It is not a weakly prime, because it can be changed into another prime (130220021300909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110010650469 + 65110010650470.
It is an arithmetic number, because the mean of its divisors is an integer number (65110010650470).
Almost surely, 2130220021300939 is an apocalyptic number.
130220021300939 is a deficient number, since it is larger than the sum of its proper divisors (1).
130220021300939 is an equidigital number, since it uses as much as digits as its factorization.
130220021300939 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 35.
The spelling of 130220021300939 in words is "one hundred thirty trillion, two hundred twenty billion, twenty-one million, three hundred thousand, nine hundred thirty-nine".
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