13022011117 has 2 divisors, whose sum is σ = 13022011118. Its totient is φ = 13022011116.

The previous prime is 13022011109. The next prime is 13022011151. The reversal of 13022011117 is 71111022031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7407356356 + 5614654761 = 86066^2 + 74931^2 .

It is a cyclic number.

It is not a de Polignac number, because 13022011117 - 2³ = 13022011109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13022011094 and 13022011103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13022015117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511005558 + 6511005559.

It is an arithmetic number, because the mean of its divisors is an integer number (6511005559).

Almost surely, 2^13022011117 is an apocalyptic number.

It is an amenable number.

13022011117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022011117 is an equidigital number, since it uses as much as digits as its factorization.

13022011117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 13022011117 its reverse (71111022031), we get a palindrome (84133033148).

The spelling of 13022011117 in words is "thirteen billion, twenty-two million, eleven thousand, one hundred seventeen".