Base | Representation |
---|---|
bin | 10010111100110001001… |
… | …111000100000100111011 |
3 | 11121111012122011002112002 |
4 | 102330301033010010323 |
5 | 132313401441420011 |
6 | 2434120053211215 |
7 | 163036520626106 |
oct | 22746117040473 |
9 | 4544178132462 |
10 | 1302201123131 |
11 | 462295649617 |
12 | 190460630b0b |
13 | 95a4913006c |
14 | 47053a3973d |
15 | 23d172b4c3b |
hex | 12f313c413b |
1302201123131 has 2 divisors, whose sum is σ = 1302201123132. Its totient is φ = 1302201123130.
The previous prime is 1302201123103. The next prime is 1302201123137. The reversal of 1302201123131 is 1313211022031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1302201123131 - 222 = 1302196928827 is a prime.
It is a super-3 number, since 3×13022011231313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1302201123137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651100561565 + 651100561566.
It is an arithmetic number, because the mean of its divisors is an integer number (651100561566).
Almost surely, 21302201123131 is an apocalyptic number.
1302201123131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302201123131 is an equidigital number, since it uses as much as digits as its factorization.
1302201123131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1302201123131 its reverse (1313211022031), we get a palindrome (2615412145162).
The spelling of 1302201123131 in words is "one trillion, three hundred two billion, two hundred one million, one hundred twenty-three thousand, one hundred thirty-one".
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