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1302201123131 is a prime number
BaseRepresentation
bin10010111100110001001…
…111000100000100111011
311121111012122011002112002
4102330301033010010323
5132313401441420011
62434120053211215
7163036520626106
oct22746117040473
94544178132462
101302201123131
11462295649617
12190460630b0b
1395a4913006c
1447053a3973d
1523d172b4c3b
hex12f313c413b

1302201123131 has 2 divisors, whose sum is σ = 1302201123132. Its totient is φ = 1302201123130.

The previous prime is 1302201123103. The next prime is 1302201123137. The reversal of 1302201123131 is 1313211022031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1302201123131 - 222 = 1302196928827 is a prime.

It is a super-3 number, since 3×13022011231313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1302201123137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651100561565 + 651100561566.

It is an arithmetic number, because the mean of its divisors is an integer number (651100561566).

Almost surely, 21302201123131 is an apocalyptic number.

1302201123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302201123131 is an equidigital number, since it uses as much as digits as its factorization.

1302201123131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1302201123131 its reverse (1313211022031), we get a palindrome (2615412145162).

The spelling of 1302201123131 in words is "one trillion, three hundred two billion, two hundred one million, one hundred twenty-three thousand, one hundred thirty-one".