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130220112331 is a prime number
BaseRepresentation
bin111100101000110111…
…0010011100111001011
3110110010021010002222101
41321101232103213023
54113142322043311
6135453340534231
712256655456161
oct1712156234713
9413107102871
10130220112331
1150253949851
12212a2551377
13c38368140a
146434805231
1535c2341ec1
hex1e51b939cb

130220112331 has 2 divisors, whose sum is σ = 130220112332. Its totient is φ = 130220112330.

The previous prime is 130220112313. The next prime is 130220112349. The reversal of 130220112331 is 133211022031.

Together with previous prime (130220112313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (130220112313) and next prime (130220112349).

It is a cyclic number.

It is not a de Polignac number, because 130220112331 - 27 = 130220112203 is a prime.

It is a super-2 number, since 2×1302201123312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130220112299 and 130220112308.

It is not a weakly prime, because it can be changed into another prime (130220112301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110056165 + 65110056166.

It is an arithmetic number, because the mean of its divisors is an integer number (65110056166).

Almost surely, 2130220112331 is an apocalyptic number.

130220112331 is a deficient number, since it is larger than the sum of its proper divisors (1).

130220112331 is an equidigital number, since it uses as much as digits as its factorization.

130220112331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 130220112331 its reverse (133211022031), we get a palindrome (263431134362).

The spelling of 130220112331 in words is "one hundred thirty billion, two hundred twenty million, one hundred twelve thousand, three hundred thirty-one".