Base | Representation |
---|---|
bin | 1011110101111110110011… |
… | …1100010101010110011011 |
3 | 1201002220010001002222200021 |
4 | 2331133230330111112123 |
5 | 3201323044401110433 |
6 | 43410122305251311 |
7 | 2512544552103622 |
oct | 275375474252633 |
9 | 51086101088607 |
10 | 13022021113243 |
11 | 417067648703a |
12 | 1563908633b37 |
13 | 735c81cc043c |
14 | 3303aa9006b9 |
15 | 178aeca8622d |
hex | bd7ecf1559b |
13022021113243 has 2 divisors, whose sum is σ = 13022021113244. Its totient is φ = 13022021113242.
The previous prime is 13022021113217. The next prime is 13022021113267. The reversal of 13022021113243 is 34231112022031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13022021113243 - 233 = 13013431178651 is a prime.
It is a super-2 number, since 2×130220211132432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13022021119243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511010556621 + 6511010556622.
It is an arithmetic number, because the mean of its divisors is an integer number (6511010556622).
Almost surely, 213022021113243 is an apocalyptic number.
13022021113243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022021113243 is an equidigital number, since it uses as much as digits as its factorization.
13022021113243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13022021113243 its reverse (34231112022031), we get a palindrome (47253133135274).
The spelling of 13022021113243 in words is "thirteen trillion, twenty-two billion, twenty-one million, one hundred thirteen thousand, two hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •