Base | Representation |
---|---|
bin | 1011110101111110110100… |
… | …0000111100101110111011 |
3 | 1201002220010010101110022221 |
4 | 2331133231000330232323 |
5 | 3201323100203320011 |
6 | 43410122351224511 |
7 | 2512544565303163 |
oct | 275375500745673 |
9 | 51086103343287 |
10 | 13022022323131 |
11 | 4170677133048 |
12 | 1563908b18137 |
13 | 735c82325053 |
14 | 3303aab375a3 |
15 | 178aecc24971 |
hex | bd7ed03cbbb |
13022022323131 has 2 divisors, whose sum is σ = 13022022323132. Its totient is φ = 13022022323130.
The previous prime is 13022022323039. The next prime is 13022022323137. The reversal of 13022022323131 is 13132322022031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13022022323131 - 27 = 13022022323003 is a prime.
It is a super-2 number, since 2×130220223231312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13022022323096 and 13022022323105.
It is not a weakly prime, because it can be changed into another prime (13022022323137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511011161565 + 6511011161566.
It is an arithmetic number, because the mean of its divisors is an integer number (6511011161566).
Almost surely, 213022022323131 is an apocalyptic number.
13022022323131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022022323131 is an equidigital number, since it uses as much as digits as its factorization.
13022022323131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13022022323131 its reverse (13132322022031), we get a palindrome (26154344345162).
The spelling of 13022022323131 in words is "thirteen trillion, twenty-two billion, twenty-two million, three hundred twenty-three thousand, one hundred thirty-one".
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