Base | Representation |
---|---|
bin | 11101100110111101000111… |
… | …010101110000001001011101 |
3 | 122002001221101022202201222122 |
4 | 131212331013111300021131 |
5 | 114032012143421110442 |
6 | 1140542215032552325 |
7 | 36300051453503414 |
oct | 3546750725601135 |
9 | 562057338681878 |
10 | 130220310331997 |
11 | 3854613a389476 |
12 | 1273169a5526a5 |
13 | 5787951656792 |
14 | 24229a786847b |
15 | 100c4e0b38dd2 |
hex | 766f4757025d |
130220310331997 has 2 divisors, whose sum is σ = 130220310331998. Its totient is φ = 130220310331996.
The previous prime is 130220310331961. The next prime is 130220310332003. The reversal of 130220310331997 is 799133013022031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122504298603556 + 7716011728441 = 11068166^2 + 2777771^2 .
It is a cyclic number.
It is not a de Polignac number, because 130220310331997 - 212 = 130220310327901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130220310331697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110155165998 + 65110155165999.
It is an arithmetic number, because the mean of its divisors is an integer number (65110155165999).
Almost surely, 2130220310331997 is an apocalyptic number.
It is an amenable number.
130220310331997 is a deficient number, since it is larger than the sum of its proper divisors (1).
130220310331997 is an equidigital number, since it uses as much as digits as its factorization.
130220310331997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 183708, while the sum is 44.
The spelling of 130220310331997 in words is "one hundred thirty trillion, two hundred twenty billion, three hundred ten million, three hundred thirty-one thousand, nine hundred ninety-seven".
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