Base | Representation |
---|---|
bin | 1011110101111110110110… |
… | …0110001111111111100011 |
3 | 1201002220010210210020112002 |
4 | 2331133231212033333203 |
5 | 3201323110204220342 |
6 | 43410123340554215 |
7 | 2512545044360123 |
oct | 275375546177743 |
9 | 51086123706462 |
10 | 13022032101347 |
11 | 4170681701615 |
12 | 156391025296b |
13 | 735c84369989 |
14 | 3303ac160c83 |
15 | 178aeda06d32 |
hex | bd7ed98ffe3 |
13022032101347 has 2 divisors, whose sum is σ = 13022032101348. Its totient is φ = 13022032101346.
The previous prime is 13022032101317. The next prime is 13022032101349. The reversal of 13022032101347 is 74310123022031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13022032101347 - 26 = 13022032101283 is a prime.
Together with 13022032101349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13022032101349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511016050673 + 6511016050674.
It is an arithmetic number, because the mean of its divisors is an integer number (6511016050674).
Almost surely, 213022032101347 is an apocalyptic number.
13022032101347 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022032101347 is an equidigital number, since it uses as much as digits as its factorization.
13022032101347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 13022032101347 its reverse (74310123022031), we get a palindrome (87332155123378).
The spelling of 13022032101347 in words is "thirteen trillion, twenty-two billion, thirty-two million, one hundred one thousand, three hundred forty-seven".
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