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13022032101347 is a prime number
BaseRepresentation
bin1011110101111110110110…
…0110001111111111100011
31201002220010210210020112002
42331133231212033333203
53201323110204220342
643410123340554215
72512545044360123
oct275375546177743
951086123706462
1013022032101347
114170681701615
12156391025296b
13735c84369989
143303ac160c83
15178aeda06d32
hexbd7ed98ffe3

13022032101347 has 2 divisors, whose sum is σ = 13022032101348. Its totient is φ = 13022032101346.

The previous prime is 13022032101317. The next prime is 13022032101349. The reversal of 13022032101347 is 74310123022031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13022032101347 - 26 = 13022032101283 is a prime.

Together with 13022032101349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13022032101349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511016050673 + 6511016050674.

It is an arithmetic number, because the mean of its divisors is an integer number (6511016050674).

Almost surely, 213022032101347 is an apocalyptic number.

13022032101347 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022032101347 is an equidigital number, since it uses as much as digits as its factorization.

13022032101347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 13022032101347 its reverse (74310123022031), we get a palindrome (87332155123378).

The spelling of 13022032101347 in words is "thirteen trillion, twenty-two billion, thirty-two million, one hundred one thousand, three hundred forty-seven".