13022032101433 has 2 divisors, whose sum is σ = 13022032101434. Its totient is φ = 13022032101432.

The previous prime is 13022032101391. The next prime is 13022032101499. The reversal of 13022032101433 is 33410123022031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12995426576889 + 26605524544 = 3604917^2 + 163112^2 .

It is a cyclic number.

It is not a de Polignac number, because 13022032101433 - 2⁴¹ = 10823008845881 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13022032101398 and 13022032101407.

It is not a weakly prime, because it can be changed into another prime (13022032107433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511016050716 + 6511016050717.

It is an arithmetic number, because the mean of its divisors is an integer number (6511016050717).

Almost surely, 2^{13022032101433} is an apocalyptic number.

It is an amenable number.

13022032101433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022032101433 is an equidigital number, since it uses as much as digits as its factorization.

13022032101433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13022032101433 its reverse (33410123022031), we get a palindrome (46432155123464).

The spelling of 13022032101433 in words is "thirteen trillion, twenty-two billion, thirty-two million, one hundred one thousand, four hundred thirty-three".