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13022132321113 is a prime number
BaseRepresentation
bin1011110101111111001110…
…0100100011101101011001
31201002220101210100221012021
42331133303210203231121
53201323311333233423
643410141321014441
72512550402256046
oct275376344435531
951086353327167
1013022132321113
114170723233173
121563939924421
13735c9c059506
143303bb5ac1cd
15178b0770195d
hexbd7f3923b59

13022132321113 has 2 divisors, whose sum is σ = 13022132321114. Its totient is φ = 13022132321112.

The previous prime is 13022132321087. The next prime is 13022132321119. The reversal of 13022132321113 is 31112323122031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9038128297104 + 3984004024009 = 3006348^2 + 1995997^2 .

It is an emirp because it is prime and its reverse (31112323122031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13022132321113 is a prime.

It is not a weakly prime, because it can be changed into another prime (13022132321119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511066160556 + 6511066160557.

It is an arithmetic number, because the mean of its divisors is an integer number (6511066160557).

Almost surely, 213022132321113 is an apocalyptic number.

It is an amenable number.

13022132321113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022132321113 is an equidigital number, since it uses as much as digits as its factorization.

13022132321113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13022132321113 its reverse (31112323122031), we get a palindrome (44134455443144).

The spelling of 13022132321113 in words is "thirteen trillion, twenty-two billion, one hundred thirty-two million, three hundred twenty-one thousand, one hundred thirteen".