Base | Representation |
---|---|
bin | 1011110101111111011110… |
… | …1101011111010001101111 |
3 | 1201002220120122001100200201 |
4 | 2331133313231133101233 |
5 | 3201323432123133434 |
6 | 43410152241334331 |
7 | 2512552204502152 |
oct | 275376755372157 |
9 | 51086518040621 |
10 | 13022201771119 |
11 | 4170759458a72 |
12 | 15639590373a7 |
13 | 735cb05648a8 |
14 | 3303c68c9c99 |
15 | 178b0d86e614 |
hex | bd7f7b5f46f |
13022201771119 has 2 divisors, whose sum is σ = 13022201771120. Its totient is φ = 13022201771118.
The previous prime is 13022201771101. The next prime is 13022201771239. The reversal of 13022201771119 is 91117710222031.
It is a weak prime.
It is an emirp because it is prime and its reverse (91117710222031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13022201771119 - 29 = 13022201770607 is a prime.
It is a super-2 number, since 2×130222017711192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13022201775119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511100885559 + 6511100885560.
It is an arithmetic number, because the mean of its divisors is an integer number (6511100885560).
Almost surely, 213022201771119 is an apocalyptic number.
13022201771119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022201771119 is an equidigital number, since it uses as much as digits as its factorization.
13022201771119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10584, while the sum is 37.
The spelling of 13022201771119 in words is "thirteen trillion, twenty-two billion, two hundred one million, seven hundred seventy-one thousand, one hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •