Base | Representation |
---|---|
bin | 1011110110000010011101… |
… | …1010000111101010110101 |
3 | 1201002222122101211012102101 |
4 | 2331200213122013222311 |
5 | 3201332102003000203 |
6 | 43410403505142101 |
7 | 2512611062361133 |
oct | 275404732075265 |
9 | 51088571735371 |
10 | 13023002000053 |
11 | 417102a1358a1 |
12 | 1563b4102a931 |
13 | 7360aa297a36 |
14 | 330460cb4753 |
15 | 178b58c3e41d |
hex | bd827687ab5 |
13023002000053 has 2 divisors, whose sum is σ = 13023002000054. Its totient is φ = 13023002000052.
The previous prime is 13023002000027. The next prime is 13023002000059. The reversal of 13023002000053 is 35000020032031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10882068244804 + 2140933755249 = 3298798^2 + 1463193^2 .
It is a cyclic number.
It is not a de Polignac number, because 13023002000053 - 225 = 13022968445621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13023002000059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511501000026 + 6511501000027.
It is an arithmetic number, because the mean of its divisors is an integer number (6511501000027).
Almost surely, 213023002000053 is an apocalyptic number.
It is an amenable number.
13023002000053 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023002000053 is an equidigital number, since it uses as much as digits as its factorization.
13023002000053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 19.
Adding to 13023002000053 its reverse (35000020032031), we get a palindrome (48023022032084).
The spelling of 13023002000053 in words is "thirteen trillion, twenty-three billion, two million, fifty-three", and thus it is an aban number and an uban number.
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