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130230224141 is a prime number
BaseRepresentation
bin111100101001001010…
…0111000010100001101
3110110010222010211202212
41321102110320110031
54113202414133031
6135454341400205
712260140432523
oct1712224702415
9413128124685
10130230224141
1150259625a16
12212a5a09065
13c3857b1b34
146435cb8313
1535c318d12b
hex1e5253850d

130230224141 has 2 divisors, whose sum is σ = 130230224142. Its totient is φ = 130230224140.

The previous prime is 130230224083. The next prime is 130230224153. The reversal of 130230224141 is 141422032031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129728912041 + 501312100 = 360179^2 + 22390^2 .

It is a cyclic number.

It is not a de Polignac number, because 130230224141 - 230 = 129156482317 is a prime.

It is a super-2 number, since 2×1302302241412 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130230224161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115112070 + 65115112071.

It is an arithmetic number, because the mean of its divisors is an integer number (65115112071).

Almost surely, 2130230224141 is an apocalyptic number.

It is an amenable number.

130230224141 is a deficient number, since it is larger than the sum of its proper divisors (1).

130230224141 is an equidigital number, since it uses as much as digits as its factorization.

130230224141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130230224141 its reverse (141422032031), we get a palindrome (271652256172).

The spelling of 130230224141 in words is "one hundred thirty billion, two hundred thirty million, two hundred twenty-four thousand, one hundred forty-one".