Base | Representation |
---|---|
bin | 1011110110000010110111… |
… | …1001111011110001010111 |
3 | 1201002222220222221010122211 |
4 | 2331200231321323301113 |
5 | 3201332312404100343 |
6 | 43410422401334251 |
7 | 2512613555031466 |
oct | 275405571736127 |
9 | 51088828833584 |
10 | 13023111003223 |
11 | 4171085716562 |
12 | 1563b71637387 |
13 | 7360c6a41459 |
14 | 33047156a9dd |
15 | 178b635c179d |
hex | bd82de7bc57 |
13023111003223 has 2 divisors, whose sum is σ = 13023111003224. Its totient is φ = 13023111003222.
The previous prime is 13023111003187. The next prime is 13023111003247. The reversal of 13023111003223 is 32230011132031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13023111003223 - 217 = 13023110872151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13023111003194 and 13023111003203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13023111006223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511555501611 + 6511555501612.
It is an arithmetic number, because the mean of its divisors is an integer number (6511555501612).
Almost surely, 213023111003223 is an apocalyptic number.
13023111003223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023111003223 is an equidigital number, since it uses as much as digits as its factorization.
13023111003223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13023111003223 its reverse (32230011132031), we get a palindrome (45253122135254).
The spelling of 13023111003223 in words is "thirteen trillion, twenty-three billion, one hundred eleven million, three thousand, two hundred twenty-three".
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