Base | Representation |
---|---|
bin | 1011110110000010111100… |
… | …1011010011000100101010 |
3 | 1201002222222111001202200202 |
4 | 2331200233023103010222 |
5 | 3201332333334113310 |
6 | 43410424442432202 |
7 | 2512614234234461 |
oct | 275405713230452 |
9 | 51088874052622 |
10 | 13023132332330 |
11 | 417109676441a |
12 | 1563b78802662 |
13 | 7360cb29b823 |
14 | 33047431d9d8 |
15 | 178b653d63a5 |
hex | bd82f2d312a |
13023132332330 has 32 divisors (see below), whose sum is σ = 23613451235136. Its totient is φ = 5171074533504.
The previous prime is 13023132332293. The next prime is 13023132332347. The reversal of 13023132332330 is 3323323132031.
13023132332330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13023132332293 and 13023132332302.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52905797 + ... + 53151383.
It is an arithmetic number, because the mean of its divisors is an integer number (737920351098).
Almost surely, 213023132332330 is an apocalyptic number.
13023132332330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13023132332330 is a deficient number, since it is larger than the sum of its proper divisors (10590318902806).
13023132332330 is a wasteful number, since it uses less digits than its factorization.
13023132332330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 284438.
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 13023132332330 its reverse (3323323132031), we get a palindrome (16346455464361).
The spelling of 13023132332330 in words is "thirteen trillion, twenty-three billion, one hundred thirty-two million, three hundred thirty-two thousand, three hundred thirty".
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