Base | Representation |
---|---|
bin | 1011110110000011000010… |
… | …0101001011011110010111 |
3 | 1201010000001010101211110101 |
4 | 2331200300211023132113 |
5 | 3201332410402103132 |
6 | 43410431043434531 |
7 | 2512614641430046 |
oct | 275406045133627 |
9 | 51100033354411 |
10 | 13023155894167 |
11 | 41710a8a97811 |
12 | 1563b84685a47 |
13 | 73610312b243 |
14 | 3304774d455d |
15 | 178b674dc7e7 |
hex | bd83094b797 |
13023155894167 has 2 divisors, whose sum is σ = 13023155894168. Its totient is φ = 13023155894166.
The previous prime is 13023155894159. The next prime is 13023155894179. The reversal of 13023155894167 is 76149855132031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13023155894167 - 23 = 13023155894159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13023155864167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511577947083 + 6511577947084.
It is an arithmetic number, because the mean of its divisors is an integer number (6511577947084).
It is a 1-persistent number, because it is pandigital, but 2⋅13023155894167 = 26046311788334 is not.
Almost surely, 213023155894167 is an apocalyptic number.
13023155894167 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023155894167 is an equidigital number, since it uses as much as digits as its factorization.
13023155894167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5443200, while the sum is 55.
The spelling of 13023155894167 in words is "thirteen trillion, twenty-three billion, one hundred fifty-five million, eight hundred ninety-four thousand, one hundred sixty-seven".
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