Base | Representation |
---|---|
bin | 11101100111001000000011… |
… | …010101111110000010100100 |
3 | 122002010001200210101020122102 |
4 | 131213020003111332002210 |
5 | 114032210221414040400 |
6 | 1140551440241551232 |
7 | 36300645466665554 |
oct | 3547100325760244 |
9 | 562101623336572 |
10 | 130232054440100 |
11 | 38550116652738 |
12 | 12733a17645518 |
13 | 5788aa3794b82 |
14 | 242339d4b5164 |
15 | 100c97bbae9d5 |
hex | 76720357e0a4 |
130232054440100 has 36 divisors (see below), whose sum is σ = 282604054305300. Its totient is φ = 52092730316160.
The previous prime is 130232054440097. The next prime is 130232054440157. The reversal of 130232054440100 is 1044450232031.
It can be written as a sum of positive squares in 6 ways, for example, as 16062316559524 + 114169737880576 = 4007782^2 + 10685024^2 .
It is a super-3 number, since 3×1302320544401003 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 106865006 + ... + 108076794.
Almost surely, 2130232054440100 is an apocalyptic number.
130232054440100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130232054440100 is an abundant number, since it is smaller than the sum of its proper divisors (152371999865200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130232054440100 is a wasteful number, since it uses less digits than its factorization.
130232054440100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2286512 (or 2286505 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 29.
The spelling of 130232054440100 in words is "one hundred thirty trillion, two hundred thirty-two billion, fifty-four million, four hundred forty thousand, one hundred".
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