Base | Representation |
---|---|
bin | 11101100111001000000111… |
… | …011011111000101111000111 |
3 | 122002010001212120120112110111 |
4 | 131213020013123320233013 |
5 | 114032210342003200403 |
6 | 1140551451133333451 |
7 | 36300650262411523 |
oct | 3547100733705707 |
9 | 562101776515414 |
10 | 130232123100103 |
11 | 38550151388a42 |
12 | 12733a36637287 |
13 | 5788ab4a847ab |
14 | 24233a8668d83 |
15 | 100c982c2356d |
hex | 7672076f8bc7 |
130232123100103 has 2 divisors, whose sum is σ = 130232123100104. Its totient is φ = 130232123100102.
The previous prime is 130232123100059. The next prime is 130232123100133. The reversal of 130232123100103 is 301001321232031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130232123100103 is a prime.
It is a super-2 number, since 2×1302321231001032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130232123100133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65116061550051 + 65116061550052.
It is an arithmetic number, because the mean of its divisors is an integer number (65116061550052).
Almost surely, 2130232123100103 is an apocalyptic number.
130232123100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130232123100103 is an equidigital number, since it uses as much as digits as its factorization.
130232123100103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 130232123100103 its reverse (301001321232031), we get a palindrome (431233444332134).
The spelling of 130232123100103 in words is "one hundred thirty trillion, two hundred thirty-two billion, one hundred twenty-three million, one hundred thousand, one hundred three".
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