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1302330111223 is a prime number
BaseRepresentation
bin10010111100111000111…
…011000111010011110111
311121111112121212100220211
4102330320323013103313
5132314133002024343
62434140542010251
7163042645203511
oct22747073072367
94544477770824
101302330111223
1146235143a249
12190497876987
1395a69a8308b
1447066c14bb1
1523d2379379d
hex12f38ec74f7

1302330111223 has 2 divisors, whose sum is σ = 1302330111224. Its totient is φ = 1302330111222.

The previous prime is 1302330111211. The next prime is 1302330111253. The reversal of 1302330111223 is 3221110332031.

It is a weak prime.

It is an emirp because it is prime and its reverse (3221110332031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1302330111223 - 25 = 1302330111191 is a prime.

It is a super-2 number, since 2×13023301112232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1302330111194 and 1302330111203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302330111253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651165055611 + 651165055612.

It is an arithmetic number, because the mean of its divisors is an integer number (651165055612).

Almost surely, 21302330111223 is an apocalyptic number.

1302330111223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302330111223 is an equidigital number, since it uses as much as digits as its factorization.

1302330111223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1302330111223 its reverse (3221110332031), we get a palindrome (4523440443254).

The spelling of 1302330111223 in words is "one trillion, three hundred two billion, three hundred thirty million, one hundred eleven thousand, two hundred twenty-three".