Base | Representation |
---|---|
bin | 11101100111001001000010… |
… | …110111000111011011111101 |
3 | 122002010011110001121001220111 |
4 | 131213021002313013123331 |
5 | 114032214412221001244 |
6 | 1140552134110350021 |
7 | 36301014056622235 |
oct | 3547110267073375 |
9 | 562104401531814 |
10 | 130233120093949 |
11 | 385506131391a4 |
12 | 127340744bb311 |
13 | 5788c134ab592 |
14 | 2423460c32cc5 |
15 | 100c9e050de34 |
hex | 767242dc76fd |
130233120093949 has 2 divisors, whose sum is σ = 130233120093950. Its totient is φ = 130233120093948.
The previous prime is 130233120093863. The next prime is 130233120093977. The reversal of 130233120093949 is 949390021332031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87587231028025 + 42645889065924 = 9358805^2 + 6530382^2 .
It is a cyclic number.
It is not a de Polignac number, because 130233120093949 - 227 = 130232985876221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130233120793949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65116560046974 + 65116560046975.
It is an arithmetic number, because the mean of its divisors is an integer number (65116560046975).
Almost surely, 2130233120093949 is an apocalyptic number.
It is an amenable number.
130233120093949 is a deficient number, since it is larger than the sum of its proper divisors (1).
130233120093949 is an equidigital number, since it uses as much as digits as its factorization.
130233120093949 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 944784, while the sum is 49.
The spelling of 130233120093949 in words is "one hundred thirty trillion, two hundred thirty-three billion, one hundred twenty million, ninety-three thousand, nine hundred forty-nine".
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