Base | Representation |
---|---|
bin | 111100101001010100… |
… | …0111100011001010011 |
3 | 110110011100001001120111 |
4 | 1321102220330121103 |
5 | 4113210240434411 |
6 | 135455050222151 |
7 | 12260233226563 |
oct | 1712250743123 |
9 | 413140031514 |
10 | 130235483731 |
11 | 50261598591 |
12 | 212a7724957 |
13 | c386903b12 |
14 | 6436886da3 |
15 | 35c387b721 |
hex | 1e52a3c653 |
130235483731 has 2 divisors, whose sum is σ = 130235483732. Its totient is φ = 130235483730.
The previous prime is 130235483723. The next prime is 130235483771. The reversal of 130235483731 is 137384532031.
It is an a-pointer prime, because the next prime (130235483771) can be obtained adding 130235483731 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130235483731 - 23 = 130235483723 is a prime.
It is a super-2 number, since 2×1302354837312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130235483711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117741865 + 65117741866.
It is an arithmetic number, because the mean of its divisors is an integer number (65117741866).
Almost surely, 2130235483731 is an apocalyptic number.
130235483731 is a deficient number, since it is larger than the sum of its proper divisors (1).
130235483731 is an equidigital number, since it uses as much as digits as its factorization.
130235483731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 40.
The spelling of 130235483731 in words is "one hundred thirty billion, two hundred thirty-five million, four hundred eighty-three thousand, seven hundred thirty-one".
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