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130241241023 is a prime number
BaseRepresentation
bin111100101001011111…
…0111001111110111111
3110110011201212120002112
41321102332321332333
54113213224203043
6135455413444235
712260333165645
oct1712276717677
9413151776075
10130241241023
1150264870083
12212a964067b
13c387b6b4ba
146437545195
1535c4117518
hex1e52fb9fbf

130241241023 has 2 divisors, whose sum is σ = 130241241024. Its totient is φ = 130241241022.

The previous prime is 130241240993. The next prime is 130241241029. The reversal of 130241241023 is 320142142031.

It is a strong prime.

It is an emirp because it is prime and its reverse (320142142031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130241241023 - 26 = 130241240959 is a prime.

It is a super-2 number, since 2×1302412410232 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130241241023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130241241029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65120620511 + 65120620512.

It is an arithmetic number, because the mean of its divisors is an integer number (65120620512).

Almost surely, 2130241241023 is an apocalyptic number.

130241241023 is a deficient number, since it is larger than the sum of its proper divisors (1).

130241241023 is an equidigital number, since it uses as much as digits as its factorization.

130241241023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130241241023 its reverse (320142142031), we get a palindrome (450383383054).

The spelling of 130241241023 in words is "one hundred thirty billion, two hundred forty-one million, two hundred forty-one thousand, twenty-three".