Base | Representation |
---|---|
bin | 1011110110000111011101… |
… | …0011011010101100011101 |
3 | 1201010010002211001121020222 |
4 | 2331201313103122230131 |
5 | 3201342323124422003 |
6 | 43411144511051125 |
7 | 2512656226636553 |
oct | 275416723325435 |
9 | 51103084047228 |
10 | 13024342420253 |
11 | 417165783038a |
12 | 1564255b10aa5 |
13 | 736261bb5898 |
14 | 33054ad17bd3 |
15 | 178bd6765c38 |
hex | bd8774dab1d |
13024342420253 has 2 divisors, whose sum is σ = 13024342420254. Its totient is φ = 13024342420252.
The previous prime is 13024342420169. The next prime is 13024342420279. The reversal of 13024342420253 is 35202424342031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13017793888324 + 6548531929 = 3608018^2 + 80923^2 .
It is an emirp because it is prime and its reverse (35202424342031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13024342420253 - 216 = 13024342354717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13024342420283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512171210126 + 6512171210127.
It is an arithmetic number, because the mean of its divisors is an integer number (6512171210127).
Almost surely, 213024342420253 is an apocalyptic number.
It is an amenable number.
13024342420253 is a deficient number, since it is larger than the sum of its proper divisors (1).
13024342420253 is an equidigital number, since it uses as much as digits as its factorization.
13024342420253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 35.
Adding to 13024342420253 its reverse (35202424342031), we get a palindrome (48226766762284).
The spelling of 13024342420253 in words is "thirteen trillion, twenty-four billion, three hundred forty-two million, four hundred twenty thousand, two hundred fifty-three".
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