Base | Representation |
---|---|
bin | 1011110110000111100001… |
… | …0101011001000001101011 |
3 | 1201010010011000121021002022 |
4 | 2331201320111121001223 |
5 | 3201342342041334143 |
6 | 43411150325455055 |
7 | 2512656526640414 |
oct | 275417025310153 |
9 | 51103130537068 |
10 | 13024359714923 |
11 | 41716665730a7 |
12 | 156425b87148b |
13 | 73626565c80b |
14 | 33054d33a80b |
15 | 178bd8030268 |
hex | bd87855906b |
13024359714923 has 2 divisors, whose sum is σ = 13024359714924. Its totient is φ = 13024359714922.
The previous prime is 13024359714829. The next prime is 13024359714959. The reversal of 13024359714923 is 32941795342031.
13024359714923 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13024359714923 - 224 = 13024342937707 is a prime.
It is not a weakly prime, because it can be changed into another prime (13024359714973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512179857461 + 6512179857462.
It is an arithmetic number, because the mean of its divisors is an integer number (6512179857462).
Almost surely, 213024359714923 is an apocalyptic number.
13024359714923 is a deficient number, since it is larger than the sum of its proper divisors (1).
13024359714923 is an equidigital number, since it uses as much as digits as its factorization.
13024359714923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4898880, while the sum is 53.
The spelling of 13024359714923 in words is "thirteen trillion, twenty-four billion, three hundred fifty-nine million, seven hundred fourteen thousand, nine hundred twenty-three".
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