Base | Representation |
---|---|
bin | 111100101001100101… |
… | …0001111000111000110 |
3 | 110110011221110110022221 |
4 | 1321103022033013012 |
5 | 4113220004224032 |
6 | 135500001242554 |
7 | 12260400346123 |
oct | 1712312170706 |
9 | 413157413287 |
10 | 130244211142 |
11 | 50266509621 |
12 | 212aa63345a |
13 | c38866b376 |
14 | 6437ab974a |
15 | 35c4502597 |
hex | 1e5328f1c6 |
130244211142 has 4 divisors (see below), whose sum is σ = 195366316716. Its totient is φ = 65122105570.
The previous prime is 130244211131. The next prime is 130244211143. The reversal of 130244211142 is 241112442031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241112442031 = 29 ⋅8314222139.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130244211143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32561052784 + ... + 32561052787.
It is an arithmetic number, because the mean of its divisors is an integer number (48841579179).
Almost surely, 2130244211142 is an apocalyptic number.
130244211142 is a deficient number, since it is larger than the sum of its proper divisors (65122105574).
130244211142 is an equidigital number, since it uses as much as digits as its factorization.
130244211142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65122105573.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 130244211142 its reverse (241112442031), we get a palindrome (371356653173).
The spelling of 130244211142 in words is "one hundred thirty billion, two hundred forty-four million, two hundred eleven thousand, one hundred forty-two".
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