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130245004333 is a prime number
BaseRepresentation
bin111100101001100110…
…1010000110000101101
3110110011222221202101101
41321103031100300231
54113220210114313
6135500030243101
712260410161463
oct1712315206055
9413158852341
10130245004333
1150266a00554
12212aa956491
13c388888402
146437c44833
1535c460c5dd
hex1e53350c2d

130245004333 has 2 divisors, whose sum is σ = 130245004334. Its totient is φ = 130245004332.

The previous prime is 130245004321. The next prime is 130245004403. The reversal of 130245004333 is 333400542031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126862767684 + 3382236649 = 356178^2 + 58157^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130245004333 is a prime.

It is a super-2 number, since 2×1302450043332 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130245004733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65122502166 + 65122502167.

It is an arithmetic number, because the mean of its divisors is an integer number (65122502167).

Almost surely, 2130245004333 is an apocalyptic number.

It is an amenable number.

130245004333 is a deficient number, since it is larger than the sum of its proper divisors (1).

130245004333 is an equidigital number, since it uses as much as digits as its factorization.

130245004333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 28.

Adding to 130245004333 its reverse (333400542031), we get a palindrome (463645546364).

The spelling of 130245004333 in words is "one hundred thirty billion, two hundred forty-five million, four thousand, three hundred thirty-three".