Base | Representation |
---|---|
bin | 111100101001100111… |
… | …0000011101000001111 |
3 | 110110012000100100012012 |
4 | 1321103032003220033 |
5 | 4113220233301222 |
6 | 135500034531435 |
7 | 12260412020102 |
oct | 1712316035017 |
9 | 413160310165 |
10 | 130245212687 |
11 | 50267033047 |
12 | 212aaa36b7b |
13 | c38892c1b5 |
14 | 6437c9a739 |
15 | 35c464e1e2 |
hex | 1e53383a0f |
130245212687 has 2 divisors, whose sum is σ = 130245212688. Its totient is φ = 130245212686.
The previous prime is 130245212609. The next prime is 130245212729. The reversal of 130245212687 is 786212542031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130245212687 - 28 = 130245212431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130245212087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65122606343 + 65122606344.
It is an arithmetic number, because the mean of its divisors is an integer number (65122606344).
Almost surely, 2130245212687 is an apocalyptic number.
130245212687 is a deficient number, since it is larger than the sum of its proper divisors (1).
130245212687 is an equidigital number, since it uses as much as digits as its factorization.
130245212687 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 41.
The spelling of 130245212687 in words is "one hundred thirty billion, two hundred forty-five million, two hundred twelve thousand, six hundred eighty-seven".
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