Base | Representation |
---|---|
bin | 11000010000101100… |
… | …11000101100011101 |
3 | 1020121201210221110111 |
4 | 30020112120230131 |
5 | 203133344103213 |
6 | 5552242410021 |
7 | 640525366516 |
oct | 141026305435 |
9 | 36551727414 |
10 | 13024987933 |
11 | 55842a2241 |
12 | 2636060911 |
13 | 12c7610569 |
14 | 8b7bd1a0d |
15 | 51373aa3d |
hex | 308598b1d |
13024987933 has 2 divisors, whose sum is σ = 13024987934. Its totient is φ = 13024987932.
The previous prime is 13024987907. The next prime is 13024987949. The reversal of 13024987933 is 33978942031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9991401849 + 3033586084 = 99957^2 + 55078^2 .
It is a cyclic number.
It is not a de Polignac number, because 13024987933 - 233 = 4435053341 is a prime.
It is a super-2 number, since 2×130249879332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13024982933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512493966 + 6512493967.
It is an arithmetic number, because the mean of its divisors is an integer number (6512493967).
Almost surely, 213024987933 is an apocalyptic number.
It is an amenable number.
13024987933 is a deficient number, since it is larger than the sum of its proper divisors (1).
13024987933 is an equidigital number, since it uses as much as digits as its factorization.
13024987933 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 979776, while the sum is 49.
The spelling of 13024987933 in words is "thirteen billion, twenty-four million, nine hundred eighty-seven thousand, nine hundred thirty-three".
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