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130250214343 = 829157117267
BaseRepresentation
bin111100101001110000…
…1001000101111000111
3110110012100202110011201
41321103201020233013
54113223023324333
6135500334043331
712260502361144
oct1712341105707
9413170673151
10130250214343
1150269939947
12212b0649547
13c389990962
1464387dd3cb
1535c4cdb17d
hex1e53848bc7

130250214343 has 4 divisors (see below), whose sum is σ = 130407332440. Its totient is φ = 130093096248.

The previous prime is 130250214319. The next prime is 130250214373. The reversal of 130250214343 is 343412052031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130250214343 - 233 = 121660279751 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130250214313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78557805 + ... + 78559462.

It is an arithmetic number, because the mean of its divisors is an integer number (32601833110).

Almost surely, 2130250214343 is an apocalyptic number.

130250214343 is a deficient number, since it is larger than the sum of its proper divisors (157118097).

130250214343 is an equidigital number, since it uses as much as digits as its factorization.

130250214343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157118096.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 130250214343 its reverse (343412052031), we get a palindrome (473662266374).

The spelling of 130250214343 in words is "one hundred thirty billion, two hundred fifty million, two hundred fourteen thousand, three hundred forty-three".

Divisors: 1 829 157117267 130250214343