Base | Representation |
---|---|
bin | 11000010000101101… |
… | …11100100000000101 |
3 | 1020121202002101122111 |
4 | 30020112330200011 |
5 | 203133413301342 |
6 | 5552245501021 |
7 | 640526550226 |
oct | 141026744005 |
9 | 36552071574 |
10 | 13025134597 |
11 | 5584392452 |
12 | 2636111771 |
13 | 12c7662247 |
14 | 8b7c2d24d |
15 | 513769217 |
hex | 3085bc805 |
13025134597 has 2 divisors, whose sum is σ = 13025134598. Its totient is φ = 13025134596.
The previous prime is 13025134589. The next prime is 13025134609. The reversal of 13025134597 is 79543152031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9657189441 + 3367945156 = 98271^2 + 58034^2 .
It is a cyclic number.
It is not a de Polignac number, because 13025134597 - 23 = 13025134589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13025134537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512567298 + 6512567299.
It is an arithmetic number, because the mean of its divisors is an integer number (6512567299).
Almost surely, 213025134597 is an apocalyptic number.
It is an amenable number.
13025134597 is a deficient number, since it is larger than the sum of its proper divisors (1).
13025134597 is an equidigital number, since it uses as much as digits as its factorization.
13025134597 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 40.
The spelling of 13025134597 in words is "thirteen billion, twenty-five million, one hundred thirty-four thousand, five hundred ninety-seven".
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