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13025407 is a prime number
BaseRepresentation
bin110001101100…
…000001111111
3220111202111111
4301230001333
511313303112
61143102451
7215466643
oct61540177
926452444
1013025407
1173971aa
124441a27
132910955
141a30c23
1512245a7
hexc6c07f

13025407 has 2 divisors, whose sum is σ = 13025408. Its totient is φ = 13025406.

The previous prime is 13025401. The next prime is 13025459. The reversal of 13025407 is 70452031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13025407 - 223 = 4636799 is a prime.

It is a super-2 number, since 2×130254072 = 339322455031298, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13025401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512703 + 6512704.

It is an arithmetic number, because the mean of its divisors is an integer number (6512704).

Almost surely, 213025407 is an apocalyptic number.

13025407 is a deficient number, since it is larger than the sum of its proper divisors (1).

13025407 is an equidigital number, since it uses as much as digits as its factorization.

13025407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 22.

The square root of 13025407 is about 3609.0728726364. The cubic root of 13025407 is about 235.2865495004.

Adding to 13025407 its reverse (70452031), we get a palindrome (83477438).

The spelling of 13025407 in words is "thirteen million, twenty-five thousand, four hundred seven".