Base | Representation |
---|---|
bin | 11000010001010011… |
… | …01010010111101011 |
3 | 1020122002022200001121 |
4 | 30020221222113223 |
5 | 203141142303232 |
6 | 5552543000111 |
7 | 640616343631 |
oct | 141051522753 |
9 | 36562280047 |
10 | 13030041067 |
11 | 558713378a |
12 | 2637899037 |
13 | 12c868c594 |
14 | 8b8749351 |
15 | 513dd7d97 |
hex | 308a6a5eb |
13030041067 has 2 divisors, whose sum is σ = 13030041068. Its totient is φ = 13030041066.
The previous prime is 13030041047. The next prime is 13030041071. The reversal of 13030041067 is 76014003031.
13030041067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13030041067 - 27 = 13030040939 is a prime.
It is a super-3 number, since 3×130300410673 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13030041047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515020533 + 6515020534.
It is an arithmetic number, because the mean of its divisors is an integer number (6515020534).
Almost surely, 213030041067 is an apocalyptic number.
13030041067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13030041067 is an equidigital number, since it uses as much as digits as its factorization.
13030041067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 13030041067 its reverse (76014003031), we get a palindrome (89044044098).
The spelling of 13030041067 in words is "thirteen billion, thirty million, forty-one thousand, sixty-seven".
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