Base | Representation |
---|---|
bin | 11101101000001000011000… |
… | …000110101001001111110011 |
3 | 122002100122222020121001101021 |
4 | 131220020120012221033303 |
5 | 114034323144242033133 |
6 | 1141043301552120311 |
7 | 36305642164306444 |
oct | 3550103006511763 |
9 | 562318866531337 |
10 | 130301122221043 |
11 | 38577439606834 |
12 | 12745292236097 |
13 | 579245ca44ac7 |
14 | 24268723852cb |
15 | 100e67052c52d |
hex | 7682181a93f3 |
130301122221043 has 2 divisors, whose sum is σ = 130301122221044. Its totient is φ = 130301122221042.
The previous prime is 130301122221013. The next prime is 130301122221047. The reversal of 130301122221043 is 340122221103031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130301122221043 - 221 = 130301120123891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130301122220999 and 130301122221017.
It is not a weakly prime, because it can be changed into another prime (130301122221047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65150561110521 + 65150561110522.
It is an arithmetic number, because the mean of its divisors is an integer number (65150561110522).
Almost surely, 2130301122221043 is an apocalyptic number.
130301122221043 is a deficient number, since it is larger than the sum of its proper divisors (1).
130301122221043 is an equidigital number, since it uses as much as digits as its factorization.
130301122221043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 130301122221043 its reverse (340122221103031), we get a palindrome (470423343324074).
The spelling of 130301122221043 in words is "one hundred thirty trillion, three hundred one billion, one hundred twenty-two million, two hundred twenty-one thousand, forty-three".
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