130301344434133 has 2 divisors, whose sum is σ = 130301344434134. Its totient is φ = 130301344434132.

The previous prime is 130301344434073. The next prime is 130301344434139. The reversal of 130301344434133 is 331434443103031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98079748004484 + 32221596429649 = 9903522^2 + 5676407^2 .

It is a cyclic number.

It is not a de Polignac number, because 130301344434133 - 2⁴¹ = 128102321178581 is a prime.

It is a super-3 number, since 3×130301344434133³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 130301344434092 and 130301344434101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130301344434139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65150672217066 + 65150672217067.

It is an arithmetic number, because the mean of its divisors is an integer number (65150672217067).

Almost surely, 2^{130301344434133} is an apocalyptic number.

It is an amenable number.

130301344434133 is a deficient number, since it is larger than the sum of its proper divisors (1).

130301344434133 is an equidigital number, since it uses as much as digits as its factorization.

130301344434133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 37.

Adding to 130301344434133 its reverse (331434443103031), we get a palindrome (461735787537164).

The spelling of 130301344434133 in words is "one hundred thirty trillion, three hundred one billion, three hundred forty-four million, four hundred thirty-four thousand, one hundred thirty-three".