13030214241041 has 2 divisors, whose sum is σ = 13030214241042. Its totient is φ = 13030214241040.

The previous prime is 13030214240977. The next prime is 13030214241043. The reversal of 13030214241041 is 14014241203031.

13030214241041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12863010942016 + 167203299025 = 3586504^2 + 408905^2 .

It is a cyclic number.

It is not a de Polignac number, because 13030214241041 - 2⁶ = 13030214240977 is a prime.

Together with 13030214241043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13030214241041.

It is not a weakly prime, because it can be changed into another prime (13030214241043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515107120520 + 6515107120521.

It is an arithmetic number, because the mean of its divisors is an integer number (6515107120521).

Almost surely, 2^{13030214241041} is an apocalyptic number.

It is an amenable number.

13030214241041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13030214241041 is an equidigital number, since it uses as much as digits as its factorization.

13030214241041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 13030214241041 its reverse (14014241203031), we get a palindrome (27044455444072).

The spelling of 13030214241041 in words is "thirteen trillion, thirty billion, two hundred fourteen million, two hundred forty-one thousand, forty-one".