Base | Representation |
---|---|
bin | 11000010001010101… |
… | …10011111001100011 |
3 | 1020122002212222012021 |
4 | 30020222303321203 |
5 | 203141231422433 |
6 | 5552553242311 |
7 | 640622036662 |
oct | 141052637143 |
9 | 36562788167 |
10 | 13030342243 |
11 | 5587319a96 |
12 | 2637a03397 |
13 | 12c87666a9 |
14 | 8b87c6dd9 |
15 | 513e4722d |
hex | 308ab3e63 |
13030342243 has 2 divisors, whose sum is σ = 13030342244. Its totient is φ = 13030342242.
The previous prime is 13030342211. The next prime is 13030342271. The reversal of 13030342243 is 34224303031.
13030342243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13030342243 - 25 = 13030342211 is a prime.
It is not a weakly prime, because it can be changed into another prime (13030382243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515171121 + 6515171122.
It is an arithmetic number, because the mean of its divisors is an integer number (6515171122).
Almost surely, 213030342243 is an apocalyptic number.
13030342243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13030342243 is an equidigital number, since it uses as much as digits as its factorization.
13030342243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13030342243 its reverse (34224303031), we get a palindrome (47254645274).
The spelling of 13030342243 in words is "thirteen billion, thirty million, three hundred forty-two thousand, two hundred forty-three".
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