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13031041421 is a prime number
BaseRepresentation
bin11000010001011010…
…11110100110001101
31020122011012111021202
430020231132212031
5203141421311141
65553020235245
7640631011256
oct141055364615
936564174252
1013031041421
115587757322
12263809bb25
1312c894c9c8
148b8929b2d
1551403449b
hex308b5e98d

13031041421 has 2 divisors, whose sum is σ = 13031041422. Its totient is φ = 13031041420.

The previous prime is 13031041367. The next prime is 13031041459. The reversal of 13031041421 is 12414013031.

13031041421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12857065321 + 173976100 = 113389^2 + 13190^2 .

It is a cyclic number.

It is not a de Polignac number, because 13031041421 - 230 = 11957299597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13031041393 and 13031041402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13031041021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515520710 + 6515520711.

It is an arithmetic number, because the mean of its divisors is an integer number (6515520711).

Almost surely, 213031041421 is an apocalyptic number.

It is an amenable number.

13031041421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031041421 is an equidigital number, since it uses as much as digits as its factorization.

13031041421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13031041421 its reverse (12414013031), we get a palindrome (25445054452).

The spelling of 13031041421 in words is "thirteen billion, thirty-one million, forty-one thousand, four hundred twenty-one".