Base | Representation |
---|---|
bin | 10010111101100111100… |
… | …110011001100111000011 |
3 | 11121120120012101220220121 |
4 | 102331213212121213003 |
5 | 132322233440212212 |
6 | 2434350354321111 |
7 | 163101234346306 |
oct | 22754746314703 |
9 | 4546505356817 |
10 | 1303113210307 |
11 | 462713487177 |
12 | 190675b89197 |
13 | 95b6309930c |
14 | 470dcc20b3d |
15 | 23d6c3ccd07 |
hex | 12f679999c3 |
1303113210307 has 2 divisors, whose sum is σ = 1303113210308. Its totient is φ = 1303113210306.
The previous prime is 1303113210299. The next prime is 1303113210317. The reversal of 1303113210307 is 7030123113031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1303113210307 - 23 = 1303113210299 is a prime.
It is a super-2 number, since 2×13031132103072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1303113210317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651556605153 + 651556605154.
It is an arithmetic number, because the mean of its divisors is an integer number (651556605154).
Almost surely, 21303113210307 is an apocalyptic number.
1303113210307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303113210307 is an equidigital number, since it uses as much as digits as its factorization.
1303113210307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 1303113210307 its reverse (7030123113031), we get a palindrome (8333236323338).
The spelling of 1303113210307 in words is "one trillion, three hundred three billion, one hundred thirteen million, two hundred ten thousand, three hundred seven".
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