Base | Representation |
---|---|
bin | 11000010001011011… |
… | …11100100100001010 |
3 | 1020122011102201200000 |
4 | 30020231330210022 |
5 | 203141434223140 |
6 | 5553023023430 |
7 | 640632032163 |
oct | 141055744412 |
9 | 36564381600 |
10 | 13031164170 |
11 | 5587830572 |
12 | 263813ab76 |
13 | 12c899383b |
14 | 8b895c76a |
15 | 51405aa30 |
hex | 308b7c90a |
13031164170 has 48 divisors (see below), whose sum is σ = 35135886240. Its totient is φ = 3474976464.
The previous prime is 13031164121. The next prime is 13031164189. The reversal of 13031164170 is 7146113031.
13031164170 is a `hidden beast` number, since 1 + 3 + 0 + 3 + 11 + 641 + 7 + 0 = 666.
It is a super-2 number, since 2×130311641702 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2678880 + ... + 2683739.
It is an arithmetic number, because the mean of its divisors is an integer number (731997630).
Almost surely, 213031164170 is an apocalyptic number.
13031164170 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13031164170 is an abundant number, since it is smaller than the sum of its proper divisors (22104722070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13031164170 is an equidigital number, since it uses as much as digits as its factorization.
13031164170 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5362641 (or 5362629 counting only the distinct ones).
The product of its (nonzero) digits is 1512, while the sum is 27.
It can be divided in two parts, 130311 and 64170, that added together give a 4-th power (194481 = 214).
The spelling of 13031164170 in words is "thirteen billion, thirty-one million, one hundred sixty-four thousand, one hundred seventy".
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