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13031206806809 is a prime number
BaseRepresentation
bin1011110110100001000001…
…1100111110010100011001
31201010202211012121120101002
42331220100130332110121
53202000402420304214
643414242002434345
72513321311155422
oct275502034762431
951122735546332
1013031206806809
11417455a579624
1215656509629b5
13736ab7088c89
143309dc852649
15178e891e31de
hexbda1073e519

13031206806809 has 2 divisors, whose sum is σ = 13031206806810. Its totient is φ = 13031206806808.

The previous prime is 13031206806803. The next prime is 13031206806823. The reversal of 13031206806809 is 90860860213031.

13031206806809 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10262111123209 + 2769095683600 = 3203453^2 + 1664060^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13031206806809 is a prime.

It is not a weakly prime, because it can be changed into another prime (13031206806803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515603403404 + 6515603403405.

It is an arithmetic number, because the mean of its divisors is an integer number (6515603403405).

Almost surely, 213031206806809 is an apocalyptic number.

It is an amenable number.

13031206806809 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031206806809 is an equidigital number, since it uses as much as digits as its factorization.

13031206806809 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 373248, while the sum is 47.

The spelling of 13031206806809 in words is "thirteen trillion, thirty-one billion, two hundred six million, eight hundred six thousand, eight hundred nine".