13031211001147 has 2 divisors, whose sum is σ = 13031211001148. Its totient is φ = 13031211001146.

The previous prime is 13031211001141. The next prime is 13031211001213. The reversal of 13031211001147 is 74110011213031.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13031211001147 is a prime.

It is a super-3 number, since 3×13031211001147³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13031211001141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515605500573 + 6515605500574.

It is an arithmetic number, because the mean of its divisors is an integer number (6515605500574).

Almost surely, 2^{13031211001147} is an apocalyptic number.

13031211001147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031211001147 is an equidigital number, since it uses as much as digits as its factorization.

13031211001147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 13031211001147 its reverse (74110011213031), we get a palindrome (87141222214178).

The spelling of 13031211001147 in words is "thirteen trillion, thirty-one billion, two hundred eleven million, one thousand, one hundred forty-seven".