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1303121133241 is a prime number
BaseRepresentation
bin10010111101101000000…
…100100111111010111001
311121120120202022110010121
4102331220010213322321
5132322243002230431
62434351240213241
7163101361605244
oct22755004477271
94546522273117
101303121133241
114627179a8854
1219067876a221
1395b64911645
14470ddcc425b
1523d6ce45611
hex12f68127eb9

1303121133241 has 2 divisors, whose sum is σ = 1303121133242. Its totient is φ = 1303121133240.

The previous prime is 1303121133217. The next prime is 1303121133247. The reversal of 1303121133241 is 1423311213031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 778215087225 + 524906046016 = 882165^2 + 724504^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1303121133241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1303121133247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651560566620 + 651560566621.

It is an arithmetic number, because the mean of its divisors is an integer number (651560566621).

Almost surely, 21303121133241 is an apocalyptic number.

It is an amenable number.

1303121133241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303121133241 is an equidigital number, since it uses as much as digits as its factorization.

1303121133241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1303121133241 its reverse (1423311213031), we get a palindrome (2726432346272).

The spelling of 1303121133241 in words is "one trillion, three hundred three billion, one hundred twenty-one million, one hundred thirty-three thousand, two hundred forty-one".