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13031222131300 = 22521011290220013
BaseRepresentation
bin1011110110100001000101…
…0111011011101001100100
31201010202212021110010121211
42331220101113123221210
53202000420331200200
643414243311121204
72513321555342302
oct275502127335144
951122767403554
1013031222131300
11417456819609a
121565655b13204
13736aba2c3219
14330a008c1272
15178e8a71daba
hexbda115dba64

13031222131300 has 36 divisors (see below), whose sum is σ = 28557729789876. Its totient is φ = 5160880048000.

The previous prime is 13031222131261. The next prime is 13031222131307. The reversal of 13031222131300 is 313122213031.

It can be written as a sum of positive squares in 6 ways, for example, as 2693852559616 + 10337369571684 = 1641296^2 + 3215178^2 .

It is a super-3 number, since 3×130312221313003 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (13031222131307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 645099907 + ... + 645120106.

It is an arithmetic number, because the mean of its divisors is an integer number (793270271941).

Almost surely, 213031222131300 is an apocalyptic number.

13031222131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13031222131300 is an abundant number, since it is smaller than the sum of its proper divisors (15526507658576).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13031222131300 is a wasteful number, since it uses less digits than its factorization.

13031222131300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1290220128 (or 1290220121 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13031222131300 its reverse (313122213031), we get a palindrome (13344344344331).

The spelling of 13031222131300 in words is "thirteen trillion, thirty-one billion, two hundred twenty-two million, one hundred thirty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 101 202 404 505 1010 2020 2525 5050 10100 1290220013 2580440026 5160880052 6451100065 12902200130 25804400260 32255500325 64511000650 129022001300 130312221313 260624442626 521248885252 651561106565 1303122213130 2606244426260 3257805532825 6515611065650 13031222131300