Base | Representation |
---|---|
bin | 1011110110100001000111… |
… | …1001010011000111010111 |
3 | 1201010202212220011011212101 |
4 | 2331220101321103013113 |
5 | 3202000430114243424 |
6 | 43414244225302531 |
7 | 2513322023656432 |
oct | 275502171230727 |
9 | 51122786134771 |
10 | 13031231009239 |
11 | 41745721aa233 |
12 | 1565658a94a47 |
13 | 736abc0b1141 |
14 | 330a01b52819 |
15 | 178e8b3c4344 |
hex | bda11e531d7 |
13031231009239 has 2 divisors, whose sum is σ = 13031231009240. Its totient is φ = 13031231009238.
The previous prime is 13031231009219. The next prime is 13031231009243. The reversal of 13031231009239 is 93290013213031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13031231009239 - 233 = 13022641074647 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13031231009198 and 13031231009207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13031231009219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515615504619 + 6515615504620.
It is an arithmetic number, because the mean of its divisors is an integer number (6515615504620).
Almost surely, 213031231009239 is an apocalyptic number.
13031231009239 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031231009239 is an equidigital number, since it uses as much as digits as its factorization.
13031231009239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 37.
The spelling of 13031231009239 in words is "thirteen trillion, thirty-one billion, two hundred thirty-one million, nine thousand, two hundred thirty-nine".
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